A real object is placed at the zero end of a meterstick. A large concave mirror at the 100 cm end of the meterstuck forms an image of the object at the 82.4 cm position. A small convex mirror placed at the 20 cm pisition form a final image at the 6.3 cm point. What is the radius of curvature of the convex mirror? Answer in unites of cm. So i know that since i have 2 mirrors the image for the 1st image will be the object for the 2nd mirror. Therefore Di= -13.6 cm Do=62.4 cm since 1/do + 1/di = 1/f f = -17.39 therefore Since r=2F r should be -17.39 cm according to my calculations but im doing something wrong cause this is not the answer!