# Multiplication of a fraction

1. Feb 28, 2009

Can anyone explain why $$\frac{-1}{x_0^2} (x - x_0) = \frac{-x}{x_0^2} + \frac{1}{x_0}$$?

Is $$\frac{-1}{x_0^2} (x - x_0) = \frac{-1}{x_0^2} . \frac{(x - x_0)}{1}$$?

After that I multiply to get $$\frac{-1}{x_0^2} (x - x_0) = \frac{-x + x_0}{x_0^2} = \frac{-x}{x_0^2} + \frac{x_0}{x_0^2}$$.

Then divide $$x_0$$ into $$x_0^2$$ which gives $$x_0^{-1}$$ which equals $$\frac{1}{x_0}$$.

The equation I am following misses all the intermediate steps so I want to make sure I am understanding it correctly.

Last edited: Feb 28, 2009
2. Feb 28, 2009

### tiny-tim

ooh, that's very complicated!

just write 1/x0 = x0/x02

3. Feb 28, 2009

### The Bob

Hey there,

Your ideas are right but, without giving too much away, there is one, small mistake in this line:

The Bob

4. Feb 28, 2009

Sorry, that was a typo, should have been $$+ \frac{x_0}{x_0^2}$$. Updated first post.