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Multiplicative groups

  1. Feb 24, 2005 #1
    Letting F be a finite field, how would one show that the multiplicative group must be cyclic?

    I know that if the order of F = n, then the multiplicative group (say, F*) has order n - 1 = m. Then g^m = 1 for all g belonging to F*.

    Thanks for your time and help.

    Last edited: Feb 24, 2005
  2. jcsd
  3. Feb 24, 2005 #2

    matt grime

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    google for multiplicative group finite field cyclic, and look at the first hit from planetmath
  4. Feb 24, 2005 #3
    thank you once again...google is great.

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