I can't figure out how to do this problem. Any help would be appreciated. Given that the curve C is defined by x=t^2-4, y=t^3+1,z=5te^(t^3+1), write an equation (in rectangular form and with integral coefficients and constants) for the normal plane to C at P (-3,0,-5). Edit: Here's what I've done. I have no idea how much is right though. The point exists where t=-1. x'=2t, y'=3t^2, z'=5e^(t^3+1)+15t^3e^(t^3+1) x=2*-1=-2, y=3*(-1)^2=3, z=-10 -2x+3y-10z= -2*-3 + 3*0 + -10*-5 -2x+3y-10z=56 Anyone know if this is correct?