Multivariable Chain Rule

  • #1
Suppose I have

F(x,y) and y=y(t) and x=x(t)

Therefore,

Ft = Fx*xt + Fy*yt. Right?

Can I write

Ftt = (Fxx*xt + Fyy*yt)*xt + Fx*xtt + (Fxx*xt + Fyy*yt)*yt + Fy*ytt

?

Basically I'm trying to figure out the second derivative by chain rule.
 
Physics news on Phys.org
  • #2
Shouldn't there be some F_xy's and F_yx's in there?
 
  • #3
You're right. I meant to write:


Ftt = (Fxx*xt + Fxy*yt)*xt + Fx*xtt + (Fyx*xt + Fyy*yt)*yt + Fy*ytt
 
  • #4
TranscendArcu said:
You're right. I meant to write:


Ftt = (Fxx*xt + Fxy*yt)*xt + Fx*xtt + (Fyx*xt + Fyy*yt)*yt + Fy*ytt

Looks ok now, good job. Just product rule and chain rule, yes?
 

Suggested for: Multivariable Chain Rule

Replies
7
Views
807
Replies
1
Views
406
Replies
5
Views
741
Replies
9
Views
921
Replies
15
Views
1K
Replies
1
Views
565
Replies
4
Views
803
Replies
3
Views
712
Replies
1
Views
688
Back
Top