1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Multivariable Functions

  1. Oct 10, 2009 #1
    1.)
    1. The problem statement, all variables and given/known data
    Sketch the domain of f(x,y,z) = ln(25-x^2-y^2-z^2) and determine it's range.

    2. Relevant equations
    N/a
    3. The attempt at a solution
    Im sure the domain is x^2+y^2+z^2 < 25 or (-infinity, 25)
    Then the range is (0,+infinity.)
    my problem is how would i sketch it.. i was thinking of a sphere with dotted outline at 5,5,5

    2.
    1. The problem statement, all variables and given/known data
    Specify the type of discontinuity at the origin of the following functions.

    2x^y/x^4+y^2
    2. Relevant equations
    N/a
    3. The attempt at a solution
    i am not sure how would i find the limit of f(x,y) as (x,y)->(0,0) so i can prove that it is either essential or removable discontinuity..

    any help would be great thanks! :D
     
  2. jcsd
  3. Oct 10, 2009 #2

    Mark44

    Staff: Mentor

    The domain is {(x, y, z) | x^2+y^2+z^2 < 25 }. This domain is a subset of three-dimensional space, not an interval as you show it.
    No. Think about the largest and smallest values that ln(25-x^2-y^2-z^2) can attain. Sure, it will always be > 0, but there is a finite value that it is always less than.
    You're on the right track with the sphere, as the domain is the interior of some sphere, but the point (5, 5, 5) is outside the sphere. I don't understand what you're trying to say with "dotted outline at 5,5,5."
    Please write this more carefully so I can clearly see what's in the denominator. Most people on this forum would interpret this as 2(xy/x4) + y2, but I suspect that isn't what you mean.
     
  4. Oct 10, 2009 #3
    So as for the first question the graph would be a sphere that is shaded inside? and then the outline of the sphere would be dotted to indicate that it wouldn't reach the radius of 5.

    As for the 2nd one ...
    the equation was 2x^2y/(x^4+y^2)
     
  5. Oct 10, 2009 #4

    Mark44

    Staff: Mentor

    Do you mean the graph of the domain of the function or the graph of the function? The domain of your function is the interior of a sphere centered at (0, 0, 0) and of radius 5.

    I haven't discussed the graph of the function, other than to say something about its domain and range.
    Well, that's what I though you meant, but I wanted to get you to write it so that it would be generally understandable.

    For the limit as (x, y) --> (0, 0) of this function to exist, it must exist independent of the path taken. Try approaching (0, 0) along different lines (y = kx) and different curves, and see if they come out the same. For different curves, you might try y = x2, y = x3, and so on.
     
  6. Oct 10, 2009 #5
    Can you clarify this?
     
  7. Oct 10, 2009 #6

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    25-x^2-y^2-z^2=25-(x^2+y^2+z^2). What's the largest value that can ever be?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Multivariable Functions
  1. Multivariable Function (Replies: 1)

Loading...