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Mutual Inductance of the cylinder coils

  1. Nov 20, 2004 #1
    Two coils are wrapped around the same cylinder form. When the current in the first coil is decreasing at a rate of -.242A/s, the induced emf in the second coil has a magnitude of .00165 Volts. What is the mutual inductance?

    What I did:

    [tex]E_2 = -M(\frac{d_i_1}{d_t})[/tex]

    .00165/-.242 = -M


    The answer given is 1.96H. I went over it several times and I keep coming back to this equation. Am I wrong, or is the book wrong?
  2. jcsd
  3. Nov 20, 2004 #2
    I assume the book's wrong, your working looks fine to me.
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