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Hi, I have to rearrange the formula to get a and b on their own. The real answers are different to mine:
p(a + b) = q (a-b) [a]
pa + pb = qa - qb
pa-qa = -qb - pb
a (p-q) = -qb - pb
a = (-qb - pb)/(p-q)
and the real answer is:
(qb + pb)/(q -p)
it's differnet to mine!
And finding rearranging to get b is
p(a + b) = q (a-b) [a]
pa + pb = qa - qb
pa-qa = -qb - pb
pb + qb = qa - pa
b(p + q) = qa - pa
b = (qa - pa)/(p + q)
and the real answer is
(pa + pa)/(q + p)
Errrrrr!
Can someone so me where i went wrong
Thanks
p(a + b) = q (a-b) [a]
pa + pb = qa - qb
pa-qa = -qb - pb
a (p-q) = -qb - pb
a = (-qb - pb)/(p-q)
and the real answer is:
(qb + pb)/(q -p)
it's differnet to mine!
And finding rearranging to get b is
p(a + b) = q (a-b) [a]
pa + pb = qa - qb
pa-qa = -qb - pb
pb + qb = qa - pa
b(p + q) = qa - pa
b = (qa - pa)/(p + q)
and the real answer is
(pa + pa)/(q + p)
Errrrrr!
Can someone so me where i went wrong
Thanks
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