Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: My proof involving Pythagorean’s Theorem

  1. Feb 27, 2010 #1
    I REALIZE THAT THIS IS A DUPLICATE. MY APOLOGIZES. PLEASE IGNORE.


    1. The problem statement, all variables and given/known data

    Let a, b, and c be lengths of sides of triangle T, where a ≤ b ≤ c.
    Prove that if T is a right triangle, then (abc)2=(c6-a6-b6)/3



    2. Relevant equations

    If T is a right triangle, then Pythagorean’s Theorem states:
    The sum of the squares of the lengths of the sides of a right triangle is equal to the square of the length of the hypotenuse. That is a2+b2=c2, where c is the hypotenuse.


    3. The attempt at a solution

    We assume the given equation and using Pythagorean’s Theorem, we obtain solutions for c2 and c6:
    We substitute these results into the original equation.
    This produces an equation where the left hand side is identical to the right hand side.
    Since these terms are equal, it follows that the original equation holds true for a right triangle.

    This is what I have. I am curious to if the proof is correct/acceptable.

    Thanks for any feedback.
     
    Last edited: Feb 27, 2010
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted