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N_0 in complexity question

  1. Oct 1, 2004 #1
    Let's say f(n) = O(g(n)), i.e. f(n) < cg(n) for some n > n_0. Does the n_0 have to be a precise point of intersection of cg(n) and f(n) or just any point for which n > n_0?

    Thanks in advance.
     
  2. jcsd
  3. Oct 2, 2004 #2

    Hurkyl

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    Any such point n_0 is fine.
     
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