Is NaHCO3 a versatile compound in aqueous solutions?

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An aqueous solution of NaHCO3 can act as both an acid and a base, illustrated by its reactions with water to produce H3O+ and NaCO3- or OH- and NaH2CO3+. The discussion highlights that the first dissociation constant (Ka1) is greater than the first base constant (Kb1), indicating that NaHCO3 predominantly acts as an acid by releasing protons. The second base constant (Kb2) is significantly larger than the second acid constant (Ka2), suggesting that the release of a second proton is less favorable. Participants debated the dominance of the reactions, noting that the equilibrium between H2CO3 and CO32- suggests both reactions occur to a similar extent. Overall, NaHCO3 demonstrates its versatility as an amphiprotic compound in aqueous solutions.
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Homework Statement



Write two equations that illustrate that an aqeous solution of NaHCO3 can act either as an acid or a base. In pure water show quantitatively which of the two reactions predominate. ka1= 4.2x10-7, Ka2=4.8x10-11


The Attempt at a Solution


as an acid:

NaHCO3(aq) + H2O(l)---> H3O+(aq) + NaCO3-(aq)

Base:

NaHCO3(aq) + H2O(l) ------> OH-(aq) + NaH2CO3+(aq)

The second part is where I am having some trouble. I am not sure if I am doing this correctly so i will try to show and explain what I think will happen as best I can. I think Ka1 will predominate the reason being that kb1= (1x10^-14)/(4.2x10^-7)=2.38x10^-8
so Ka1>Kb1 therefore this reaction will proceed. Meaning most of the sodium bicarbonate will act as an acid and release protons. whereas Kb2=(1x10^-14)/(4.8x10^11)=2.08x10^-4.
so Kb2>>Ka2 so releasing a 2nd proton is not very favorable the species is much more likely to pick up another proton then it is to release another proton.
 
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I guess if I am correct then the fact that Ka1 is quantitatively greater then kb1 is the proof that ka1 will predominate.
 
Your written reactions are good. For which dissocation of bicarbonate is more favorable, check the Na2CO3 hydrolysis steps on the way towards H2CO3, or check the dissocation steps of H2CO3 toward Na2CO3. You know how to find Ka from corresponding Kb, right?
 
How does NaHCO3 become Na2CO3? I am not sure exactly what you mean by checking the Na2CO3 hydrolysis steps on the way towards H2CO3.
 
Synergix, maybe I was sloppy with my terminology or notation. You were on a good track with your idea of comparing the acidic dissociation constant for bicarbonate to the equilibrium constant for HCO3- + H20 <===> H2CO3 + OH-
Are you studying weak acid-base equilibria right now? If so, you will soon know how to evaluate those constants.
 
Ya we have covered that already as part of the last section. I will look at it again maybe I can figure it out thanks.
 
pH of amphiprotic salt

I am not sure you can say which of the reactions dominate. If you will read through the lecture you will find that ratio [H2CO3]/[CO32-] is close to 1, that means both reactions proceed to the same degree.
 

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