How can the integral of a complex function be simplified?

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In summary, the conversation discusses finding the integral of sin(e^-x) + e^x cos(e^-x) and the attempts at solving it using substitution and integration by parts. The final solution involves transforming the cos function into a sin function and using integration by parts.
  • #1
gaobo9109
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Homework Statement



[itex] \int sin e^{-x}+e^x cos e^{-x}\,dx[/itex]

Find the integral above

Homework Equations





The Attempt at a Solution



I tried substituting [itex]u=e^{-x}[/itex], but i get [itex] \int \frac{sin u}{u}+\frac{cos u}{u^2} \,du[/itex], which is non-integrable function.
 
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  • #2
What is the derivative of ##e^x\cos(e^{-x})##?

ehild
 
  • #3
Thanks. I didn't notice that
 
  • #4
You are welcome.

ehild
 
  • #5
ehild said:
What is the derivative of ##e^x\cos(e^{-x})##?

ehild

A second way is to try to transform the cos into a sin function. That leads to the hope that an integration by part will work by starting with

[itex] e^x cos (e^{-x}) = \frac{d e^x}{dx} \cos (e^{-x}) [/itex]

and sure enough that works.
 

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A "Nasty Integration problem" refers to a difficult or complex mathematical integration problem that is typically challenging to solve using traditional integration techniques. These problems often involve complex functions or a combination of different functions, making it difficult to find an exact solution.

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