I've got a simple question that's been bugging me for a while. I think I know where the problem is, I'd just like a formal mathematical reason why I can't say this:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] \ln{(-1)}^2 = \ln(1) = 0 [/tex]

That part is fine...but then:

[tex] \ln{(-1)}^2 = 2 \ln(-1) = 2 (i \pi) [/tex]

when they should obviously be equal.

It presumably displays the fact that you can't take the square and put it in front of the log as a "2" when you're dealing with logs of negative numbers. I'd like to know if there's any formal theory behind why this can't be done.

Thanks!

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# Natural Log of negative number

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