- #1

- 3

- 0

ln(x+4)=2

i tried this

ln(x+4)=2

e^2=(x+4)

ln e^2=ln(x+4)

2=ln(x+4)

and round and round i go.... where do i start to go wrong?

- Thread starter fieldlandman
- Start date

- #1

- 3

- 0

ln(x+4)=2

i tried this

ln(x+4)=2

e^2=(x+4)

ln e^2=ln(x+4)

2=ln(x+4)

and round and round i go.... where do i start to go wrong?

- #2

- 703

- 13

you actually went the right way till the second line:

Continue there with solving FOR x!fieldlandman said:when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2

e^2=(x+4)

- #3

- 3

- 0

that was it! thanks!

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