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Natural log question

  1. Sep 24, 2005 #1
    when trying to solve

    ln(x+4)=2

    i tried this

    ln(x+4)=2
    e^2=(x+4)
    ln e^2=ln(x+4)
    2=ln(x+4)

    and round and round i go.... where do i start to go wrong?
     
  2. jcsd
  3. Sep 24, 2005 #2
    Welcome to physicsforums fieldlandman,

    you actually went the right way till the second line:

    Continue there with solving FOR x!
     
  4. Sep 24, 2005 #3
    thanks!

    that was it! thanks!
     
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