Natural log question

  • #1
fieldlandman
3
0
when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2
e^2=(x+4)
ln e^2=ln(x+4)
2=ln(x+4)

and round and round i go... where do i start to go wrong?
 

Answers and Replies

  • #2
Edgardo
705
15
Welcome to physicsforums fieldlandman,

you actually went the right way till the second line:

fieldlandman said:
when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2
e^2=(x+4)

Continue there with solving FOR x!
 
  • #3
fieldlandman
3
0
thanks!

that was it! thanks!
 

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