- #1

fieldlandman

- 3

- 0

ln(x+4)=2

i tried this

ln(x+4)=2

e^2=(x+4)

ln e^2=ln(x+4)

2=ln(x+4)

and round and round i go... where do i start to go wrong?

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- Thread starter fieldlandman
- Start date

- #1

fieldlandman

- 3

- 0

ln(x+4)=2

i tried this

ln(x+4)=2

e^2=(x+4)

ln e^2=ln(x+4)

2=ln(x+4)

and round and round i go... where do i start to go wrong?

- #2

Edgardo

- 705

- 15

you actually went the right way till the second line:

fieldlandman said:when trying to solve

ln(x+4)=2

i tried this

ln(x+4)=2

e^2=(x+4)

Continue there with solving FOR x!

- #3

fieldlandman

- 3

- 0

that was it! thanks!

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