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Natural log

  1. May 5, 2014 #1
    Why is e^-1 the inverse of natural log e? Thank you
     
  2. jcsd
  3. May 5, 2014 #2

    mathman

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    Your question is confusing. Let y = ln(x), then x = ey. If x = e, y = 1.
     
  4. May 5, 2014 #3
    Well I was reading a section on charging/ discharging capacitors and this is what it said: charge on a capacitor builds up on the capacitors plates exponentially, indicated in the passage by the repeated appearance in the charge equation of e^-1, the inverse of the natural log e. And I think the equation they are referring to is Q=Qmax(1- e^-1).
     
  5. May 5, 2014 #4

    mfb

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    Could it mean "the inverse of the [basis of the] natural log[,] e"? As e-1 = 1/e
     
  6. May 5, 2014 #5

    Ok I'll go with that because it's what I was thinking too. Thank you!
     
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