- #1

- 18

- 0

I was trying to figure out what will be the y value for this equations:

1 - e^-0.15*10^-5*y = 0.1

Could somebody help me in this??????????? The answer is supposed to be 70,240.

thanks.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter alextsipkis
- Start date

- #1

- 18

- 0

I was trying to figure out what will be the y value for this equations:

1 - e^-0.15*10^-5*y = 0.1

Could somebody help me in this??????????? The answer is supposed to be 70,240.

thanks.

- #2

- 533

- 5

1 - e^-0.15*10^-5*y = 0.1

What does that mean?

1 - (e^-0.15)*(10^-5)*y = 0.1

1 - (e^-0.15)*(10^(-5*y)) = 0.1

1 - (((e^-0.15)*10)^-5)*y = 0.1

1 - e^(-0.15*(10^(-5*y))) = 0.1

1 - e^(-0.15*(10^-5)*y) = 0.1

1 - e^(-0.15*(10^(-5*y))) = 0.1

- #3

- 18

- 0

Note that the parameter lambda has this value:

lambda = (0.15*10^-5)

And i was trying to calculate,

(1 - e^(-lambda*y)) = 0.1 for y, and the answer is assumed to be 70,240.

Similarly,

1 - e^(-lambda*y) = 0.632, and the answer for this is supposed to be 666,667.

I am really confused how we get to this answer. I am not sure wether we use log or ln to get this answer.

thanks.

- #4

- 533

- 5

- #5

- 18

- 0

I tried, but not getting the right answer.

Could somebody clear this confusion...

thanks.

Could somebody clear this confusion...

thanks.

- #6

- 533

- 5

Last edited by a moderator:

- #7

- 18

- 0

Thanks a lottttttttt gel...i got it right now.... :-)

Share: