Different people, different reasons for being here I often need help since some of my teachers don't know the answers to my problems (yes, even they are human), but I feel I need to give back to the community, so I help out where I can. Of course, ultimately we are all here to learn a thing or two.Ahh, I see. By factorising with one of the logarithm rules, I get the ln to one number equals the ln to another number, thus the numbers must be the same.
Thanks, this + other tasks are to be handed in on Monday:)
PS, not sure if this was put in the correct forum.
So, anyway. Those of you who answer our questions. Who, or what, are you? Students? Educated people just coming in here regularly to answer?
Regards, Compaq
Um not quite.I got:
x = -14 V x = 11
Is that correct?
Sure, do it however you like. Factoring, using the quadratic formula and completing the square all work.Yeah, I screwd up with the general forumula for quadrics (or whatever you call itXD), so I tried with that other way (which I don't know the English term of).. (I add (b/2)^{2} and then add -(b/2)^{2} ) I got the same factors as you, at least.
Not exactly. For [tex]ln(a), a>0[/tex]And we're dealing with the logarithm function, so x > 0, negative numbers, nor sero, have logarithms, logically. So:
(x+4)(x-1) < 0 when 0<x<1
Does that seem right, then:)
And thanks a lot:D
I'm not exactly sure what you're asking. Create another help threadOne more question, how do you add fractions and all that stuff, I feel I'm using a werid method here:P
Sorry I've never heard of factor tables, so I wouldn't know what they are.Ohh, and I always use factor tables...