1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Nautralization Reactions

  1. Apr 17, 2007 #1
    Write equations for the neutralization reactions that result in the formation of the following salts:

    lithium carbonate
    H2CO3 + LiO2 --> LiCO3 + H2O

    copper (II) chlorate
    2HClO3 + CuO --> Cu(ClO3)2 + H2O

    aluminium sulphate
    2Al(OH3) + 3H2SO4 + 10H2O --> Al2(SO4)3 * 16H2O

    ammonium iodide
    20HN3O + 13H2O + 30I2 --> 60NH4I + 20H2O

    This is all pretty new to me so could someone take a quick look at this and tell me know if I am doing it correctly? If I understand the process, water is a bi-product of the neutralization process. I also tried to find known acids or bases to base the left side equation off.
    Last edited: Apr 17, 2007
  2. jcsd
  3. Apr 17, 2007 #2


    User Avatar
    Homework Helper
    Education Advisor
    Gold Member

    Your cupric chlorate reaction seems good.
    Your lithium carbonate reaction looks like an error.
    Try better, [tex] \[
    H_2 CO_3 \; + \;Li_2 O\; \Rightarrow \;Li_2 CO_3 \; + \;H_2 O
    \] [/tex]
  4. Apr 18, 2007 #3


    User Avatar

    Staff: Mentor

    Neutralization reaction is a reaction between acid and BASE, not between acid and oxide as you wrote in the first two cases. Ammonium iodide is made when NH3(aq) (or NH4OH, or NH3.H2O, you may see different notations) reacts with HI (hydroiodic acid).
    Last edited: Apr 18, 2007
  5. Oct 23, 2008 #4
    i'm taking the same course, i got
    lithium carbonate
    2 LiOH + H2CO3 = 2 H2O + Li2CO3
    copper (II) Chlorate
    2 HCl)3+ Cu(OH)2 = 2 H2O + Cu(ClO3)2
    aluminum sluphate
    3 H2SO4 + 2 Al(OH)3 = 6 H2O + Al2(SO4)3
    ammonium iodide
    HI + NH4OH = H2O + NH4I

    I'm not compleatly sure if these are right but if someone can verify this it would be helpful
  6. Oct 23, 2008 #5


    User Avatar

    Staff: Mentor

    Looks OK. As I have already signalled earlier - ammonia can be tricky, as it is not necesarilly in the form of NH4OH.

    Or rather it is not in this form for sure, but your prof may want this form.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook