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## Homework Statement

A computer is reading data from a rotating CD-ROM. At a point that is 0.030 m from the center of the disc, the centripetal acceleration is 118 m/s2. What is the centripetal acceleration at a point that is 0.050 m from the center of the disc?

## Homework Equations

Ac=v^2/r-centripual acceleration

possibly v=2pier/T

## The Attempt at a Solution

Aa=Va^2/Ra

Ab=Vb^2/Rb

substituted Va=1.667*r*a, 1.667*ra<<<1.667 I got by dividing .050m/.030m to get the ratio of the radius'

I set up the equations like this:

118^2/.5^2=(1.667*118 m/s^2*V)^2/(1.667*.30)

>>crossed multiplied .25(196.706V)^2=13924(.5001)

solved for V and got V=.720<<<this is wrong

I think I'm on the right track I think theres an error on the way I set up my equations before substituting in the numbers.

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