- #1

rockersdash

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A basketball player is standing 9.5 m from the basket, which is at a height of 3.1m. she throws the ball from a initial height of 2m at an angle of 35 degrees above the horizontal. The ball goes through the basket. Determine intial velocity.

2. Homework Equations

Vx = Dx/t

v2^2 = v1^2 + 2ad

Dy = (V sine∅) - 0.5GT^2

3. The Attempt at a Solution

I took only half the parabola diagram and assumed v2 is 0 m/s

Vert

v1 = ?

v2 = 0 m/s

a = -9.8 m/s^2

max height = 1.1 m

I used the equation

v2^2 = v1^2 + 2ad

and got v1 as 4.64 m/s and from there on on I found initial velocity at an angle.

BUT the textbook gives a different answer (11m/s) as the initial velocity at an angle.

I can't figure out why I'm getting this wrong and my teacher sasys she will come back to me as she can't figure the mistake in mine... so help LOL

PS I assumed the max height of the parabola of the ball is 1.1 m otherwise I couldn't think of any other way.

Am I doing to this problem right? please post your work if any :)