# Need calc help 1 last time.

punjabi_monster
hi there i am having trouble on the following question.

1. ln(x+y) = e^3x
(1/x+y)(1+(dy/dx)) = (e^3x)(3)
what can u substititue for y?

Last edited:

Homework Helper
punjabi_monster said:
hi there i am having trouble on 2 quesitons.

1. ln(x+y) = e^3x
(1/x+y)(1+(dy/dx)) = (e^3x)(3)
what can u substititue for y?
I take it you are finding dy/dx by implict differentiation?
$$\log(x+y)=e^{3x}$$
differentiation yeilds
$$\frac{1+\frac{dy}{dx}}{x+y}=3e^{3x}$$
solving for dy/dx
$$\frac{dy}{dx}=3(x+y)e^{3x}-1$$
observe x+y=exp(exp(3x))
$$\frac{dy}{dx}=3e^{e^{3x}}e^{3x}-1$$
simplify
$$\frac{dy}{dx}=3e^{3x+e^{3x}}-1$$
observe that one could solve the original equation for y and obtain a more straitforward solution.
$$\log(x+y)=e^{3x}$$
solve for y
$$y=e^{e^{3x}}-x$$
differentiate
$$\frac{dy}{dx}=3e^{e^{3x}}e^{3x}-1$$

Nylex
You're not meant to do people's work for them :/.

punjabi_monster
how do u get e^e^3x

Knavish
By solving the natural log.

punjabi_monster
ok thanks guys.

Homework Helper
In general, however, when doing an implicit differentiation, it is not necessary nor desirable to solve for y and then substitute that for y in the expression for the derivative. It is better to leave it in terms of both x and y.