Can a Monkey Rearrange Letters to Spell Illinois and Tennessee?

  • Thread starter uiuc2014
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In summary, the conversation is about a probability problem involving rearranging letters to spell "Illinois" and "Tennessee". The question is about the difference in calculations using two different methods, one using 8!/(3!*2!*1!*1!*1!) and the other using (8)*(5)*(3)*(2)*(1)//(3)//(2)//(1)//(1)//(1). The expert summarizer is unsure of what the "former one" refers to and suggests that the calculations are not exactly two times larger than each other.
  • #1
uiuc2014
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I just meet some easy problem like this,
Does a monkey have a better chance of rearranging
or
I I I L L N O S to spell I L L I N O I S
E E E E N N S S T to spell T E N N E S S E E ?

For ILLINOIS
there are 3"I",2"L",1"N",1"O",1"S".
So P(Illinois)= 8!/(3!*2!*1!*1!*1!)
My question is that why the answer of ( 8 )*( 5 )*( 3 )*( 2 )*( 1 )
////////////////////////////////////////////( 3 )//( 2)//( 1 )//( 1 )/( 1 )

is exactly 2 times larger than the former one?


(8)
(3)means selecting 3 out of 8
 
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  • #2
uiuc2014 said:
I just meet some easy problem like this,
Does a monkey have a better chance of rearranging
or
I I I L L N O S to spell I L L I N O I S
E E E E N N S S T to spell T E N N E S S E E ?

For ILLINOIS
there are 3"I",2"L",1"N",1"O",1"S".
So P(Illinois)= 8!/(3!*2!*1!*1!*1!)
My question is that why the answer of ( 8 )*( 5 )*( 3 )*( 2 )*( 1 )
////////////////////////////////////////////( 3 )//( 2)//( 1 )//( 1 )/( 1 )

is exactly 2 times larger than the former one?
What "former one" are you talking about?
[tex]\frac{8!}{3! 2!}= \frac{8(7)(6)(5)(4)(3!)}{3! 2!}[/tex]
and we can cancel the "3!" in numerator and denominator. That leaves
[tex]\frac{8(7)(6)(5)(4)}{2}= 3360[/tex]

If you are saying that the "answer" (to what question) is
[tex]\frac{8(5)(3)(2)(1)}{3(2)}= 8(5)= 40[/tex]
neither is twice the other.


(8)
(3)means selecting 3 out of 8
But what does that have to do with this question?
 

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