1. May 8, 2012

mcguiry03

μ=αθ
σ^2=αθ^2
can someone show me how to prove that the mean and variance is equal to what is at the top... tnx a lot...

2. May 8, 2012

chiro

Hey mcguiry03 and welcome to the forums.

You need to specify what the distribution is and what you are trying to do.

If you are starting with a distribution X and you have Y =aX and want to find the mean and variance of Y then you use the fact that E[Y] = E[aX] = aE[X] and Var[Y] = Var[aX] = a^2Var[X].

If it is something else, then you will need to specify what is going on and what you are trying to do.

3. May 8, 2012

tnx sir