:uhh: Ok any help appreciated,(adsbygoogle = window.adsbygoogle || []).push({});

First the question:

Q)A block is attached to a horizontal spring and oscillates back and forth on a frictionless horizontal surface at a frequency of 3.00 Hz. The amplitude of the motion is 5.08x10^-2 m. At the point where the block has its maxiumum speed, it suddenly splits into two identical parts, only one part remaining attached to the spring. A) what is the amplitude and the frequency of the simple harmonic motion that exists after the block splits? b) repeat part a), assuming that the block splits when it is at one of its extreme positions.

This question is more conceptual I guess.

A)

Ok the max speed is when x=0.

So, when the mass splits in half, the kinetic energy will be reduced by half.

Since that is true, the potential energy is reduced by half. Since elastic potential energy is defined as Pe=1/2kx^2 and since Pe is halved. The amplitude will be smaller by square root (2) or 2^1/2. Makes sense as the mass is less, the extension is less. Ok the frequency relationship can be found by w=square root(k/m). So if the mass is halved, then w will have to be multiplied by square root(2). Makes sense as the mass is halved, oscillates more.

In part B, I don't get what difference it makes if the block broke at the extreme ends...help here? Would it really make a difference, the only thing that I see will change is that the speed is no longer at max, and x is no longer at 0.

Thanks. :tongue2:

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# Homework Help: Need Help at attempted problems !

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