A m=64.6kg object is released from rest at a distance h = 0.93176R above the Earth's surface, where R is the radius of the earth. Find the speed of the object when it strikes the Earth's surface. (Neglect any atmospheric friction.) G=9.8 m/s^2. For the Earth, R=6.38x10^6 m, M=5.98x10^24 kg. It implies that the gravitational acceleration at the surface of the earth is g=9.8 m/s^2.) Caution: You must take into account that the gravitational acceleration depends on the distance between the object and the center of the earth. Answer in units of m/s.(adsbygoogle = window.adsbygoogle || []).push({});

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Need help, confused.

**Physics Forums | Science Articles, Homework Help, Discussion**