A m=64.6kg object is released from rest at a distance h = 0.93176R above the Earth's surface, where R is the radius of the earth. Find the speed of the object when it strikes the Earth's surface. (Neglect any atmospheric friction.) G=9.8 m/s^2. For the Earth, R=6.38x10^6 m, M=5.98x10^24 kg. It implies that the gravitational acceleration at the surface of the earth is g=9.8 m/s^2.) Caution: You must take into account that the gravitational acceleration depends on the distance between the object and the center of the earth. Answer in units of m/s.(adsbygoogle = window.adsbygoogle || []).push({});

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