(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

msatellite = 6000 kg ;

Mearth = 5:98 £ 1024 kg ;

Rearth = 6:37 £ 106 m; and

G = 6:67259 £ 10¡11 Nm2=kg2 :

The radius of the satellite around the center

of the Earth is r =13/2R.

Hint: You may Find it useful to take into account that the gravitational force is a conservative force.

Hint: The universal gravitational force law

is F= GMm/r^2.

Caution: Neglect the rotational kinetic energy due to the Earth's rotation.

Find the energy required to launch a satellite from Earth into the circular orbit at the

specified radius r =13/2R. Answer in units of J.

2. Relevant equations

F = GMm/r^2.

U(gravitational) = GMm/r

kinetic energy (translational) = 1/2mV^2 = (1/2GMm)/r

3. The attempt at a solution

Total energy = Kinetic + Ug = 0.5GMm/r - GMm/r = -2.8911e10 J

but it is wrong

please help

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# Homework Help: Need help-Energy of satellite

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