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Need help fast on one thing

  1. Apr 12, 2005 #1
    Hey guys,
    I was wondering how to solve this equation. I tihnk I got it, but I wanna make sure so I don't go on doing all of my homework wrong.

    Question: sqrt (Y+6) - sqrt (3y) = 3

    I forget if I have to sqaure each seperate or the whole left side as FOIL. Please let me knwo asap so I can finish homeowkr :) Again, thanks so much!

    -Phil
     
  2. jcsd
  3. Apr 12, 2005 #2

    dextercioby

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    U'll have to square twice.And each time separate a sqrt in one side of the equation.

    [tex] \sqrt{y+6}-\sqrt{3y}=3\Rightarrow y+6+3y-2\sqrt{\left(y+6\right)3y}=9 [/tex]

    and then isolate in one member of the equation that sqrt and then square again.

    Daniel.
     
  4. Apr 12, 2005 #3
    Ok, waht i tohught :) Thanks Dan.
     
  5. Apr 12, 2005 #4

    dextercioby

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    I hope u can solve the quadratic that will follow.And to check whether the solutions u get are larger than 0...

    Daniel.
     
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