# Need help fast on one thing

1. Apr 12, 2005

### perpetual-burn

Hey guys,
I was wondering how to solve this equation. I tihnk I got it, but I wanna make sure so I don't go on doing all of my homework wrong.

Question: sqrt (Y+6) - sqrt (3y) = 3

I forget if I have to sqaure each seperate or the whole left side as FOIL. Please let me knwo asap so I can finish homeowkr :) Again, thanks so much!

-Phil

2. Apr 12, 2005

### dextercioby

U'll have to square twice.And each time separate a sqrt in one side of the equation.

$$\sqrt{y+6}-\sqrt{3y}=3\Rightarrow y+6+3y-2\sqrt{\left(y+6\right)3y}=9$$

and then isolate in one member of the equation that sqrt and then square again.

Daniel.

3. Apr 12, 2005

### perpetual-burn

Ok, waht i tohught :) Thanks Dan.

4. Apr 12, 2005

### dextercioby

I hope u can solve the quadratic that will follow.And to check whether the solutions u get are larger than 0...

Daniel.