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Homework Help: Need help fast

  1. Mar 6, 2005 #1
    what is the name of the curve where its radial vector drawn from the origin intersects the curves tangent line at a=3pi/4 or 135 degree at every point???

    can anybody even show me how the curve looks like or what is the general eqaution of this curve????

  2. jcsd
  3. Mar 6, 2005 #2
    Take the genaral equation of the radial vector as y=mx and tangent line as y= m1x + c1. Let the point of intersection be (x1, y1). This means both the above equations should be satisefied by (x1,y1). So plug in x1, y1 and get m and m1 in terms of x1, y1 and c1. Now use the fact that the angle 'a' between two lines is given by tan (a) = m2 - m1 / (1 + m2m1). You will get an expression in terms of x1, y1 and c1. This is the equation of the curve. Should look familiar.

    Note: This may be a long way. There may be short cuts. I can't think of any right now. :zzz:
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