- #1

bohemian

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You have been given a bottle of hydrated oxalic acid (contains

*x*number of water molecules) with a half-torn label, and have been asked to determine the exact formula of this compound. Your best guess on the formula of this molecule is [tex]H_{2}C_{2}O_{4} \bullet xH_{2}O[/tex]. To figure out the exact formula of this compund, you make a solution by taking 5.00g of this compound, dissolve it in exactly 250mL of water. You then remove 25.0mL of this solution and titrate it with 0.500 M sodium hydroxide. You find that the solution requires 15.9mL of the base for neutralization. Based on this experiment, determine the exact formula of the compound (you need to determine

*x*).

If anyone can walk me through this and help me get the answer, I'd really appreciate it.