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Need help finishing this problem off

  1. Oct 3, 2005 #1
    1.05 = (ViSin30)10 * ViCos30+ 1/2(-9.8)(10/ViCos30)^2


    help me solve for Vi please
     
  2. jcsd
  3. Oct 3, 2005 #2

    robphy

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    Can you do some algebra to separate out the factors of Vi in each term on the right-hand side?
    You might want to take care in using parenthesis around (ViCos30), especially in the second term on the right-hand side.
     
  4. Oct 3, 2005 #3
    all the #'s i'm getting are turning out wrong
     
  5. Oct 3, 2005 #4

    robphy

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    Let's go slowly... do algebra first (arithmetic last). It's easier to spot an algebra mistake.

    Can you factor "(ViSin30)10 * ViCos30" ?
    It may help to forget the numbers and think of this symbolically as [tex](V_i A)B * V_iC[/tex]. So, can you factor this expression and write it in terms of [tex]V_i[/tex], [tex]A[/tex], [tex]B[/tex], and [tex]C[/tex]?
     
  6. Oct 3, 2005 #5
    "Can you factor "(ViSin30)10 * ViCos30" ?"


    4.33Vi
     
  7. Oct 3, 2005 #6

    robphy

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    almost... correct coefficient...
    check the units of that term
     
  8. Oct 3, 2005 #7
    i dont understand why that isnt correct


    ViSin(30)*10 * ViCos(30)
    Vi.5 * 10 * Vi .87
    Vi 4.4
     
  9. Oct 3, 2005 #8

    robphy

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    that term should have a Vi^2
     
  10. Oct 3, 2005 #9
    anychance you can give me a walk through numerically to the answer? i'm afraid that'll help me more then me struggling here
     
  11. Oct 3, 2005 #10

    robphy

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    In summary (up to this point):
    ViSin(30)*10 * ViCos(30) = Vi^2 4.4

    You've done fine with the coefficient, although you missed the fact that Vi is squared.
    But you've gotten passed that. In other words, algebra (rather than arithmetic) is your problem.

    Now, work on factoring "1/2(-9.8)(10/ViCos30)^2", which you should really write as (1/2)(-9.8)(10/ (ViCos30) )^2... especially if you try to plug something like this into your calculator.
     
  12. Oct 3, 2005 #11
    unfortunately i'm not too good at more involved algebra like this :frown:


    (1/2)(-9.8)(10/ (ViCos30) )^2


    -4.9(100/Vi^2* .75)


    so


    4.4Vi^2 -4.9(100/.75Vi^2) :frown:
     
    Last edited: Oct 3, 2005
  13. Oct 3, 2005 #12

    Integral

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    I do not see anyway to give "a walk through numerically" with out doing the algebra first.

    Is this the starting point:

    [tex] 1.05 = V_i Sin(30) * 10 * V_i Cos(30) + \frac {-9.8} {2} \frac {10} {{(V_i Cos(30))}^2}[/tex]
     
  14. Oct 3, 2005 #13
    yes that is the starting point

    except it's (10/ViCos30)^2

    the whole thing squared
     
  15. Oct 3, 2005 #14
    n/m :frown:
     
    Last edited: Oct 3, 2005
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