Understanding the Proof of Theorem 5.1 in a Complex Analysis Paper

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In summary, the conversation discusses the proof of Theorem 5.1, also known as equation (53), on page 16 of a paper being read. It is mentioned that multiplying equation (22) by (s-1) and differentiating with respect to s at s=1 would not be the same as Corollary 5.2. The use of the limit definition in computing the derivative is suggested, with equation (41) being relevant in this context. It is clarified that (22) is only valid when s is not 1, and at s=1, f(1) is defined as 1 due to the presence of a simple pole in \Phi(1,s,u) with residue 1
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benorin
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The paper I am reading is http://arxiv.org/PS_cache/math/pdf/0506/0506319.pdf ).

I am trying to follow the proof of Theorem 5.1 [a.k.a. eqn. (53)] on pg. 16. Multiplying (22) by (s-1) and differentiating w.r.t. s at s=1 wouldn't be the same as Corrollary 5.2 since s=1, right? So instead use the limit definition, e.g. using

[tex]\frac{\partial f(1)}{\partial s} = \lim_{s\rightarrow 1} \frac{f(s)-f(1)}{s-1} [/tex]

to compute the derivative, is this the right direction? How does (41) come into play here?

Thanks in advance for getting sucked far enough into my problem to post a reply

-Ben
 
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I haven't read this very thoroughly, but that looks correct on why cor. 5.2 doesn't apply. (22) was only valid when s was not 1.

The limit is the right idea for the derivative. When you multiply by (s-1) in (22), you get an expression for [tex]f(s)=(s-1)\Phi(1,s,u)[/tex] that's valid when s is not 1. At s=1, you define f(1) to be 1 as [tex]\Phi(1,s,u)[/tex] has a simple pole there with residue 1. (41) is

[tex]\lim_{s\rightarrow 1}\frac{(s-1)\Phi(1,s,u)-1}{s-1}[/tex]

which is the derivative of this f(s) at s=1.
 
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Thank you shmoe! That makes it vividly clear to me.

-Ben
 

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