Calculating Final Speed and Direction of a Moving Object in a Collision

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In summary, a force of 1200N is applied to a 0.4kg steel ball moving at 14m/s in a collision lasting 27ms. With the force in the opposite direction of the initial velocity, the final speed and direction of the ball can be found using the equation FΔt=mv, resulting in a final speed of 67m/s in the negative direction.
  • #1
vongola13th
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Homework Statement


A force that averages 1200N is applied to a 0.4kg steel ball moving at 14m/s in a collision lasting 27ms. If the force is in a direction
opposite the inital velocity of the ball ,find the final speed and direction of the ball


Homework Equations



n/a

The Attempt at a Solution


I used FdeltaT=mv
1200(27x10^-3)=0.4(v2-v1)
32.4=0.4v2-5.6
38/0.4=v2
95m/s =V2. Is this correct?
 
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  • #2
Fdt = Δp is a vector equation.
You have defined the impulse FΔt as positive, so v1 is negative.
 
  • #3
rude man said:
Fdt = Δp is a vector equation.
You have defined the impulse FΔt as positive, so v1 is negative.

so it would be 32.4-5.6=26.8
26.8/0.4=67m/s?
Is this right?
 
  • #4
vongola13th said:
so it would be 32.4-5.6=26.8
26.8/0.4=67m/s?
Is this right?

Yes it is.
 
  • #5


I would like to commend you for using the appropriate equations to solve this problem. Your calculation of the final velocity is correct, but it is important to also consider the direction of the final velocity. Since the force is acting in the opposite direction of the initial velocity, the final velocity will also be in the opposite direction. Therefore, the final speed of the ball will be 95m/s in the opposite direction of its initial velocity. It is always important to consider both magnitude and direction in physics calculations. Keep up the good work!
 

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