So f(x)= x(√x-1)
The Attempt at a Solution
So i understand that the derivitive of a mutiple is (f x g) prime
f'xg + fxg'
(1)(√x-1) + (x)(1/2x^-1/2)
now im stuck...
ive used the equation (f(x)-f(x))/x-a and i ended up with x^3/2 -1
but when i used (f')(g)+(f)(g)'
i get 3/2x^1/2 - 1
and now i am just really confused... i could really use some help :D