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Hello, i have a question. This is integral question, but i don't have any program to write the equation with:
integral (sin5x)^(-2) dx= ?
Thank you..
integral (sin5x)^(-2) dx= ?
Thank you..
cristo said:This is one of those you should really know, since it can be rewritten cosec^{2}(5x).
However, if you don't know the antiderivative, then it can be worked out by a few substitutions, the first being u=sin(5x)
cristo said:It's your homework, not mine! Show how you did the first substitution, and we'll go from there.
If you've substituted, why do you still have functions of x in the integral? If you let u=sin(5x), then du=5cos(5x)dx=5[sqrt(1-u^{2})]. This transforms your integral to [tex]5 \int \frac{du}{u^2\sqrt{1-u^2}}[/tex].Mag|cK said:ok sorry
if i substitute with sin5x,
integral (sin5x)^(-2) d(sin5x)/5cos5x
this is how far i can get if i substitute with sin5x as i can't eliminate the cos5x.
If you look back, I said you'll need a few substitutions!I already tried substituting with cosec5x and sec5x, but still no solution.
jakcn001 said:With -d[cot(x)]=(sinx)^(-2) dx ,you can solve it easily.Have a try!