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Hello, i have a question. This is integral question, but i dont have any program to write the equation with:
integral (sin5x)^(-2) dx= ?
Thank you..
integral (sin5x)^(-2) dx= ?
Thank you..
yes i have done using substitution method but can't solve the problem. Can you step by step show me how please? thxThis is one of those you should really know, since it can be rewritten cosec2(5x).
However, if you don't know the antiderivative, then it can be worked out by a few substitutions, the first being u=sin(5x)
ok sorryIt's your homework, not mine! Show how you did the first substitution, and we'll go from there.
If you've substituted, why do you still have functions of x in the integral? If you let u=sin(5x), then du=5cos(5x)dx=5[sqrt(1-u2)]. This transforms your integral to [tex]5 \int \frac{du}{u^2\sqrt{1-u^2}}[/tex].ok sorry![]()
if i substitute with sin5x,
integral (sin5x)^(-2) d(sin5x)/5cos5x
this is how far i can get if i substitute with sin5x as i cant eliminate the cos5x.
If you look back, I said you'll need a few substitutions!I already tried substituting with cosec5x and sec5x, but still no solution.
I did allude to that in my first post.With -d[cot(x)]=(sinx)^(-2) dx ,you can solve it easily.Have a try!