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1st of all please give me some guidance since im a new here and please remind me if im do wrong in term of my wrongly area of posting, i just want to make some freinds and to share the knowledge wif all of u guys, thanks for supporting and thanks for all ur help and guide

thanks agains

http://img216.imageshack.us/img216/20/22129520.png [Broken]

i need ur help regarding this, ive tried by my self but im soo sure that ive done wrongly

here it comes

the figure shows that how i oversizing the hex 1/2" nut by oversizing machine. the pressure which is 3.5kg/mm sq is push the nut thru the tapper of a 100 mm length. how can i determine the time taken,t for the nut to going thru the 100mm tapper

here is the detail that may required

size of nut: 1/2 inch hexagonal nut (internal dia of nut = 1/2 inch)

pressure, P: 3.5kg/mm sq

tapper length,L: 100mm

Power of machine: 5HP

Speed: 750 rpm

time, t = ???

i

when im try to solve the problem, im using this equation

1. P=Fa (find F)

2. W=F x S (find W) work = f x s

3. P= W/ t (find t) power = w/t

ive once try to determine the force exist by

then once i get the F, ive determine the work done by

lastly ive tried to find the time,t by using

but im not satisfied with the answer that i got,

can anybody correct me if im wrong or giving me for some tips or correct formula on how to done iti would very great of any possible idea and i'll tried by myself before refer to all of u back

if u hv any question or didnt understand wif the question, please ask me and i would really great to explain

thanks again

regards

thanks agains

## Homework Statement

http://img216.imageshack.us/img216/20/22129520.png [Broken]

i need ur help regarding this, ive tried by my self but im soo sure that ive done wrongly

here it comes

the figure shows that how i oversizing the hex 1/2" nut by oversizing machine. the pressure which is 3.5kg/mm sq is push the nut thru the tapper of a 100 mm length. how can i determine the time taken,t for the nut to going thru the 100mm tapper

here is the detail that may required

size of nut: 1/2 inch hexagonal nut (internal dia of nut = 1/2 inch)

pressure, P: 3.5kg/mm sq

tapper length,L: 100mm

Power of machine: 5HP

Speed: 750 rpm

time, t = ???

i

## Homework Equations

when im try to solve the problem, im using this equation

1. P=Fa (find F)

2. W=F x S (find W) work = f x s

3. P= W/ t (find t) power = w/t

## The Attempt at a Solution

ive once try to determine the force exist by

**P=F/A:**then once i get the F, ive determine the work done by

**W=F x S**;lastly ive tried to find the time,t by using

**P= W/t**which is P is a power of machine while W is a work donebut im not satisfied with the answer that i got,

**here is my work**1st.To find area of 1/2” inch hex nut (im not sure if it is correct)

area of hex nut?? = 6as + Ph

= 6(2)(1.2) + 7.2 (1.1)

= 22.32cm

wheres a= apothem length

s= side length

perimeter of the base= 6 * s

= 6 * (1.2)

= 7.2

2nd. Find Force, F

(converting 3.5kg/mm sq into unit pascal I got 34.3MPa)

P=F/A

F=PA

=34.3Mpa * (22.32 x 10-2)

F= 7.66 x 106 N

3rd. Det work done

W = F * S

= 7.66 x 106 (100 x 10-3)

W= 765.6 x 103 N

4th find time, t

P=W/t

t=W/P

where p= power of machine =5HP = 3730 watt ??????????

t=765.6 x 103 N / 3730

?????????????final answer; t=205 sec

can anybody correct me if im wrong or giving me for some tips or correct formula on how to done iti would very great of any possible idea and i'll tried by myself before refer to all of u back

if u hv any question or didnt understand wif the question, please ask me and i would really great to explain

thanks again

regards

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