Need help on Radiation

  • Thread starter andrew410
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  • #1
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At high noon, the Sun delivers 1,000 W to each square meter of a blacktop road. If the hot asphalt loses energy only by radiation, what is its equilibrium temperature?

I know the formula for energy rate of radiation:
[tex] P = \sigma A e T^4 [/tex]
I don't know how to apply this to the problem...
Any help would be great! Thx in advance ! :)
 

Answers and Replies

  • #2
Tide
Science Advisor
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If the blacktop is in thermal or radiative equilibrium it radiates the same amount of energy it absorbs.
 
  • #3
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So do I solve for T for the above formula and plug in the values? If so, then what is the emissivity(e)?
 
  • #4
Tide
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e = 1 for an ideal radiator.
 
  • #5
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thanks a lot!!! :)
 

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