- #1

- 26

- 0

Im very confused how to do this :/

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- Thread starter vaxopy
- Start date

- #1

- 26

- 0

Im very confused how to do this :/

- #2

- 40

- 0

Remember that torque = u X B where u is the magnetic dipole moment of the loop. Since there is no requirement for the magnitude or direction of B, you can just let B=1 and be perpendicular to u so that u X B = u.

- #3

- 80

- 0

it seems too easy..

t = torque, s=square, r=rectangle

t = NIABsino (o = theta)

ts/tr = NIAsB/NIArB = As/Ar = L^2/2L^2 = 1/2

is this right?

- #4

- 40

- 0

Use a different variable to define the sides of the rectangle then use the fact that the perimeters are the same to find the sides of the reactangle in terms of L.

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