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Need help regarding the derivation of a 2-particle wavefunction
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[QUOTE="TSny, post: 6198000, member: 229090"] If you take ##|p, q \rangle## as corresponding to ##\frac{1}{\sqrt{2}}( |p \rangle |q \rangle + |q \rangle ||p \rangle)## and ##|x, y \rangle## as corresponding to ##\frac{1}{\sqrt{2}} (|x \rangle |y \rangle + |y \rangle |x \rangle )##, [SIZE=16px][FONT=Noto Sans][COLOR=rgb(29, 29, 29)]then ## \langle y, x | p, q \rangle## will not yield the factor of ##\frac{1}{\sqrt{2}}## in Blundell's (3.40). If you want to get that factor, it appears that you would have to take ##|x,y\rangle## as corresponding to ## \frac{1}{2} ( |x \rangle |y\rangle + |y \rangle |x\rangle )## which has an overall factor of ##\frac{1}{2}## instead of ##\frac{1}{\sqrt{2}}##. This corresponds to the extra factor of ##\frac{1}{\sqrt{2!}}## that Blundell includes in his definition of the change of basis from the basis ##|p, q \rangle ## to the basis ##|x, y \rangle##.[/COLOR][/FONT][/SIZE] [/QUOTE]
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Need help regarding the derivation of a 2-particle wavefunction
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