# Need help solving for a variable

1. Sep 16, 2006

### Joules23

can someone show the steps to go from
Here:

To Here:

2. Sep 16, 2006

$$x = \frac{-b \pm\sqrt{b^2-4ac}}{2a}$$

In the expression you have, note:
$$a = \frac{1}{2}a_y$$
$$b = v_0$$
$$c = -y$$

3. Sep 16, 2006

### Joules23

ahhh OK, thanks for that

Last edited: Sep 16, 2006