- #1

willworkforfood

- 54

- 0

The question "A speeder passes a parked police car at a constant speed of 39.3 m/s. At that instant the police car starts from rest with a uniform acceleration of 2.03m/s^2. How much time t in seconds passes before the speeder is overtaken by the police car?"

For practical purposes of this problem, can I assume "speed" to be equivalent to velocity? Is uniform acceleration the same thing as constant acceleration? Finally, when they say the speeder is "overtaken" by the police car, do they mean when the two position values are equal to each other and to find that corresponding t value?

Thanks in advance