How Do You Solve Physics Problems Involving a Pulley System with Two Students?

  • Thread starter driedupfish
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In summary, we have a situation where a rope of negligible mass and a pulley of negligible mass are attached to the ceiling. Student A of mass 70 kg is holding one end of the rope while standing on the floor, and Student B of mass 60 kg is suspended at rest on the opposite end of the rope. We are asked to calculate the magnitude of the force exerted by the floor on Student A, which can be found by using Newton's 2nd law. We then move on to part C where we are asked to calculate the tension in the rope while Student B is accelerating at a constant rate of 0.25 m/s2. To answer this, we need to consider all the forces acting on Student B
  • #1
driedupfish
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2a66pap.jpg

A rope of negligible mass passes over a pulley of negligible mass attached to the ceiling, as shown above. One end of the rope is held by Student A of mass 70 kg, who is at rest on the floor. The opposite end of the rope is held by Student B of mass 60 kg, who is suspended at rest above the floor.


(b) Calculate the magnitude of the force exerted by the floor on Student A.
(c) Student B now climbs up the rope at a constant acceleration of 0.25 m/s2 with respect to the floor.
Calculate the tension in the rope while Student B is accelerating.

(d) As Student B is accelerating, is Student A pulled upward off the floor? Justify your answer.

(e) With what minimum acceleration must Student B climb up the rope to lift Student A upward off the floor?

i was working on this question for a long time but i kept getting it wrong.
 
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  • #2
Show us what you've done so far and tell us where you are stuck. Here's a hint: Since the rope is masseless and the pulley is massless and frictionless, there will be a single tension throughout the rope.
 
  • #3
i am now on part C, i think that since student A and B are both at rest at the first place, student B climbing up just adds another force to the tension, so .25 * mass of student B. = force of tension.
 
  • #4
Careful. Newton's 2nd law tells you that the net force equals "ma". (Tension is not the only force on B.)
 
  • #5
How do you do this question?
 

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