Q. A Man, is pushing a copier machine, up an incline, which weighs 600 N. I need to find the frictional force, and the normal force. The free body diagram, I shall describe that to you. Weight of the machine acting downards. and if we resolve this weight we get mg sin theta along the incline , and mg cos theta acting downward. Friction is acting in the direction opposite to the applied force. The force applied is 180 N, at an angle of 10 degrees, which when resolved, given F cos theta in the x and F sin theta in the y. Normal force is acting perpendicular to the surface. Now, if we were to sum the forces in the x and y x : F cos theta - F friction - mg sin theta = 0 y : F sin theta + Normal force - mg cos theta = 0 I have the theta, for the F cos theta which is 10 degrees, and the weight of the block which is 600 N. How do I find, out the angle which the machine makes, with the incline, so that this may be used, to calculate mg sin theta & mg cos theta. I've spent nearly 2hours with this problem, and have seemed to exhausted all possibilities. Guys, any ideas please help !