I'll try to make this short, but this thread deals with the dice game bunco. Briefly, in the game, there are many different rounds, and in each round, you are trying to roll a certain number with 3 dice. So if we are going for 2's, we roll 3 dice and get points for how many 2's show up. If you end up rolling all 3 dice of the number that you are going for in that round, then it is called a Bunco. So in our example, we are going for 2's, and if we roll three 2's, then we get a bunco. If we roll three 4's, though, it is not a bunco. So my question is what the probability is that you will roll 9 bunco's throughout 5 games (you go for each dice number 5 times, so 30 rounds altogether). I know that the probability of rolling 3 of a kind is 1 out of 6^3, so one of 216. But then you have to do that 9 times...so multiply that by 9. But then you have to take into account that it has to be the correct number you are rolling for, and that's where I get confused. Anybody know the answer?