I'll try to make this short, but this thread deals with the dice game bunco.(adsbygoogle = window.adsbygoogle || []).push({});

Briefly, in the game, there are many different rounds, and in each round, you are trying to roll a certain number with 3 dice. So if we are going for 2's, we roll 3 dice and get points for how many 2's show up.

If you end up rolling all 3 dice of the number that you are going for in that round, then it is called a Bunco. So in our example, we are going for 2's, and if we roll three 2's, then we get a bunco. If we roll three 4's, though, it is not a bunco.

So my question is what the probability is that you will roll 9 bunco's throughout 5 games (you go for each dice number 5 times, so 30 rounds altogether).

I know that the probability of rolling 3 of a kind is 1 out of 6^3, so one of 216. But then you have to do that 9 times...so multiply that by 9. But then you have to take into account that it has to be the correct number you are rolling for, and that's where I get confused.

Anybody know the answer?

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# Need help with dice probability

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