1. The problem statement, all variables and given/known data In the figure below, the pendulum consists of a uniform disk with radius r = 10 cm and mass 755 g attached to a uniform rod with length L = 500 mm and mass 290 g. (a) Calculate the rotational inertia of the pendulum about the pivot. kg·m2 (b) What is the distance between the pivot and the center of mass of the pendulum? m (c) Calculate the period of oscillation. s 2. Relevant equations Icomrod=1/12 ML^2 Icomdisk=1/4 MR^2+ 1/12 ML^2 I=Icom + Mh^2 T=2pi sqrt(I/Mgh) 3. The attempt at a solution Irod=Icomrod + Mh^2= 1/12 ML^2+ Mh^2 Idisk=Icomdisk +Mh^2=1/4 MR^2+ 1/12 ML^2+Mh^2= 1/4 MR^2+Mh^2 the 1/12ML^2 =0 because the disk has no width. I=Irod + Idisk=.221Kgm^2 webassign said .221 was wrong and I have no Idea what I did.