Need help with Frictional Force

In summary, on a 32.5° incline, a car weighing 1.07 x 10^4 N has each wheel bearing an equal part of its weight, resulting in a vertical downward force of 2.68 x 10^3 N at the center of each wheel. With a tire radius of 35 cm and a brake radius of 20 cm, the frictional force exerted by the road on each wheel can be determined. Additionally, the sum of the magnitudes of the frictional forces applied by the brakes to the wheel can also be calculated.
  • #1
bbhoh44
2
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Homework Statement


A car weighing 1.07 104 N is at rest on a 32.5° incline. Each wheel bears an equal part of the car's weight. Thus the axles apply a vertical downward force of 2.68 103 N to the center of each wheel. The tire radius is 35 cm and the brake radius is 20sm
(a) Find the frictional force exerted by the road on each wheel.


(b) Find the sum of the magnitudes of the frictional forces fB applied by the brakes to the wheel, as shown in the figure below.



Homework Equations





The Attempt at a Solution

 

Attachments

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  • #2
what is 20sm?
 
  • #3
SORRY IT SHOULD READ 20 cm
 

What is frictional force?

Frictional force is the force that opposes the motion of an object when it comes into contact with another object or surface.

What factors affect frictional force?

The factors that affect frictional force include the nature of the surfaces in contact, the weight of the objects, and the presence of any lubricants or fluids.

How is frictional force calculated?

Frictional force can be calculated by multiplying the coefficient of friction by the normal force, which is the force perpendicular to the surface of contact.

What is the difference between static and kinetic friction?

Static friction is the force that prevents an object from moving when it is at rest, while kinetic friction is the force that opposes the motion of an object when it is already in motion.

How can frictional force be reduced?

Frictional force can be reduced by using lubricants or by changing the nature of the surfaces in contact to reduce their roughness or increase their smoothness.

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