- #1

- 128

- 0

but i got stuck here

what is

lim f(x) = lim ln [(x + 2)/(x - 1)] =???

x→-2- x→-2-

how do u solve for this?

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- Thread starter gillgill
- Start date

- #1

- 128

- 0

but i got stuck here

what is

lim f(x) = lim ln [(x + 2)/(x - 1)] =???

x→-2- x→-2-

how do u solve for this?

- #2

VietDao29

Homework Helper

- 1,424

- 3

[tex]\lim_{x \rightarrow -2 ^ -} \frac{x + 2}{x - 1}[/tex]? Note that the numerator tends to 0, while the denominator tends to -3.

Then what can you say about:

[tex]\lim_{x \rightarrow 0 ^ +} \ln x[/tex]?

Viet Dao,

- #3

- 128

- 0

that would be -infinity??

how about

lim f(x) = lim ln [(x + 2)/(x - 1)] =???

x→-2+ x→-2+

how about

lim f(x) = lim ln [(x + 2)/(x - 1)] =???

x→-2+ x→-2+

- #4

Diane_

Homework Helper

- 390

- 1

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