- #1
mike305
- 4
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Need help solving this problem
http://img409.imageshack.us/img409/5854/chp851yx1.jpg
Thank you
http://img409.imageshack.us/img409/5854/chp851yx1.jpg
Thank you
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mike305 said:the momentum before the release is 0, and after is 2. I understand that i need to apply conservation of momentum in this problem somehow, but I don't see a way so far.
mike305 said:v2 = 2/3 m/s ( to the left) ?
and for part b, should I use convservation of energy (potential and kinetic) in order to find the height?
mike305 said:thank you very much for your help
Momentum is a measure of an object's motion, specifically its mass and velocity. It is calculated by multiplying an object's mass by its velocity.
In a closed system, the total momentum before a collision is equal to the total momentum after the collision. This means that the total momentum of all objects involved in the collision remains the same, even if individual objects may change their velocity.
An elastic collision is a type of collision in which kinetic energy is conserved. This means that both momentum and kinetic energy are conserved before and after the collision. In an elastic collision, the objects involved bounce off each other without any loss of energy.
An inelastic collision is a type of collision in which kinetic energy is not conserved. Some of the kinetic energy is lost during the collision, usually in the form of heat or sound. In an inelastic collision, the objects may stick together after colliding.
In a collision, the momentum of an object is directly proportional to its mass. This means that a heavier object will have a greater momentum than a lighter object if they have the same velocity. In a collision between two objects, the larger object will usually experience a smaller change in velocity compared to the smaller object due to its larger mass.