So here's the problem(adsbygoogle = window.adsbygoogle || []).push({});

Conside the dissolution of CaCl2:

CaCl2(s) ---> Ca^(2+) (aq) + 2Cl^(-1) (aq) deltaH = -81.5kJ

An 11.0g sample of CACl2 id dissolved in 125g of water, with both substances at 25.0°C. Calculate the final temperature of the solution assuming no heat lost to the surroundings and assuming the solution has a specific heat capacity of 4.18 J/(°C*g).

So far I think it's just q(rxn) = q(water) + q(CaCl2)

(136g)(4.184J/°Cg)(Tfinal - 25.0°C) = (125g)(4.184)(Tfinal - 25.0°c) + (11g)c(Tfinal - 25.0°C)

But it seems that I am missing C for the calcium chloride and I don't know what to do about it? is there another way to calculating it without C of CaCl2?

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# Need help with simple calorimetry problem

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