Need help with simple quantum problem

  • Thread starter einai
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Hi, I came across a problem which seems to be pretty simple, but I'm stuck :confused: .

Given a Hamiltonian:
[tex]H=\frac{\vec{p}^2}{2m}+V(\vec{x})[/tex]

If |E> is a bound state of the Hamiltonian with energy eigenvalue E, show that: [tex]<E| \vec{p} |E>=0[/tex]

-----------------------------------
So I've been trying something like this:

[tex]\frac{1}{2m}<E|\vec{p} \cdot \vec{p}|E> + <E|V(\vec{x})|E> = E<E|E> = E[/tex]

but I have no idea how to proceed from here. I don't think I'm on the right track actually.

Thanks in advance!
 
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Answers and Replies

  • #2
Doc Al
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FYI: This question has been answered in the quantum physics forum.
 

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