Find M in \int_{-\frac{\pi}{2}}^{M} \cos x dx= 1.5 with Expert Tips

  • Thread starter ziddy83
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In summary, to solve for M in the given equation, you can use the antiderivative of cos, which is sin. Then, setting the antiderivative equal to 1.5, you can solve for M by subtracting the initial value of -π/2. After realizing there was a typo in the second post, the correct equation is sin M + 1 = 1.5.
  • #1
ziddy83
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Hey what's up..I need a little help with the following problem.

If [tex]\int_{-\frac{\pi}{2}}^{M} \cos x dx= 1.5}[/tex], find M.

How do I go about doing this? I know that...the anti derivative of cos is sin, and that [tex] \sin x \right]_{-\frac{pi}{2}}^{M} = 1.5[/tex]

Any help would be greatly appreciated...
 
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  • #2
[tex]\sin x |^M_{-\pi/2} = \sin M - (-\pi/2) = 1.5[/tex]

Are you ok from there?
 
  • #3
ahhh..DUH! goshh...how did i NOT see that? Thanks man...haha...
 
  • #4
It was a typo/error in post #2.

[tex] \sin x\left |_{-\frac{\pi}{2}}^{M}\right =1.5\Rightarrow \sin M+\sin\frac{\pi}{2}=1.5\Rightarrow \sin M +1 =1.5[/tex]

Daniel.
 
  • #5
Oops! You're right, of course.
 

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An integral is a mathematical concept that represents the area under a curve on a graph. In science, it is used to calculate quantities such as velocity, acceleration, and volume, which are important in understanding various phenomena.

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Integrals can be complex and difficult to solve, especially when dealing with real-world problems. Scientists may need help with integrals to accurately model and understand the behavior of physical systems.

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